10x^2+6x-1060=0

Solution for 10x^2+6x-1060=0 equation:

10x^2+6x-1060=0

a = 10; b = 6; c = -1060;
Δ = b2-4ac
Δ = 62-4·10·(-1060)
Δ = 42436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{42436}=206$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-206}{2*10}=\frac{-212}{20}
=-10+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+206}{2*10}=\frac{200}{20}
=10
$